Adidas headphones include photovoltaic cells and cost in any sort of sunshine – Picture and sound – Information

1Ah of battery capability appears a bit a lot to me, however let’s assume that for the sake of comfort.
Nonetheless, it’s essential to additionally be certain that your charging circuit reaches the minimal voltage.
The voltage drop throughout a single PV cell is kind of low (relying on the kind of cell), so you need to put a number of in sequence.
If you happen to do not, then it’s essential to not solely have the ability to carry the voltage down, but additionally up, so you’ve got a buck-boost converter. They’re usually not very environment friendly.

Anyway, let’s assume a superbly matching voltage of the PV cells.
You continue to have to provide at the very least about 14 mA of present to cost such a battery in 100 hours.
The rule of thumb is that you need to put in roughly 1.4x the quantity of vitality to cost a battery with a specific amount of vitality.
14 mA at 3.6V (customary lithium cell voltage) = 50 mWatt.

Nonetheless, we’re going to calculate how large your PV panel must be.
A considerably customary quantity of sunshine is “60 Watt mild bulb above the eating desk”.
That’s say a 6 to 7 Watt LED lamp on a floor of 1.5 m^2
So to light up 1 cm^2 you want roughly 50 mWatt of vitality which you place within the LED lamp.
Nonetheless, such a LED lamp is simply 30 to 35% environment friendly (if you have already got a very good one).
So that you successfully have about 50 mWatt of sunshine at 3 cm^2 in your desk.
Then take moderately environment friendly PV cells that obtain 20% effectivity and then you definately want 15 cm^2 of PV cells to realize 14 mA charging present in a fairly well-lit room.
This with optimum placement and orientation of the panels.

Briefly, with 1mA of “quiescent present” you do not actually get a lot time for charging.
Nonetheless, many DC/DC circuits simply draw 5 – 10 mA of “leakage present” if you’re not cautious.

Edit:
Correction to the calculation. I haven’t got to do all of it by coronary heart, particularly not with a beer

That’s say a 6 to 7 Watt LED lamp on a floor of 1.5 m^2
So to light up 1 cm^2 you want roughly 50 mWatt of vitality which you place within the LED lamp.

1.5 m^2 is 15000 cm^2
So then you’ve got 7Watt / 15000 cm^2 = 0.5 mWatt per cm^2
Briefly, the remainder nonetheless must be adjusted downwards by an element of 100.
Then you do not want 15 cm^2 of panels, however 1500 cm^2, or greater than 2 A4 sheets to get 14 mA charging present.

[Reactie gewijzigd door TD-er op 16 augustus 2022 23:32]